After a summary, and then some examples of what NOT to do, I want to show how you can apply this skill that of evaluating resonance forms in determining electron density on a molecule toward figuring out the reactivity of a given molecule.
Next Post: In Summary — Resonance. I wonder this question too. The difference should be quite small. One could make the argument that the form on the right has a more substituted double bond, so it should make a greater contribution to the resonance hybrid. Your email address will not be published. Save my name, email, and website in this browser for the next time I comment. Notify me via e-mail if anyone answers my comment.
This site uses Akismet to reduce spam. Learn how your comment data is processed. Previous Resonance Structures Practice. Polar Aprotic? It only takes a minute to sign up. Connect and share knowledge within a single location that is structured and easy to search.
By electronegativity, you would expect the nitrogen ligand to hold the metal's d electrons more strongly, but in the case of ammonia vs. The lone pair is used to form sigma bond with metal. No extra electron to give to metal and also no d orbital to accept electron from metal. Sign up to join this community. The best answers are voted up and rise to the top.
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